PROGRAM FOR BISECTION METHOD
Hello friends aapka swagat hai ek or naye topic par. Aaj main
aapke liye Lekar Aaya hun ki aap bisection method program kese create
kar satte ho.
PROGRAM FOR BISECTION METHOD
# include<stdio.h>
# include<conio.h>
# include<math.h>
# include<string.h>
floateqn(float);
void main()
{
float x1=2,x2=3,x3,z,t, rng=.005;
int i=1;
clrscr();
printf("\n equation is :
X^4-34X-9 \n");
do
{
printf("\n iteration %d: \n",
i);
x3=(x1+x2)/2;
printf("x3=%f",x3);
z=eqn(x3);
printf("\n f(%f)=%f",x3,z);
if(z>0)
x2=x3;
else
x1=x3;
printf("\n x1=%f\tx2=%f \n",x1,x2);
i++;
}
while((fabs(x1-x2))>0.005);
printf("\n finalanswer=%f \n",x3);
getch();
}
/**** function for given
equation***/
floateqn(float x)
{
float f;
f = x*x*x-4*x-9;
return(f);
}
Output….
Equation is : X^4-34X-9
Iteration 1:
x3=2.500000
f(2.500000)=-3.375000
x1=2.500000 x2=3.000000
iteration 2:
x3=2.750000
f(2.750000)=0.796875
x1=2.500000 x2=2.750000
iteration 3:
x3=2.625000
f(2.625000)=-1.412109
x1=2.625000 x2 =2.750000
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