PROGRAM FOR BISECTION METHOD

Hello friends aapka swagat hai ek or naye topic par. Aaj main aapke liye Lekar Aaya hun ki aap bisection method program kese create kar satte ho.

Aaj mein easily way mei pura program mention karne ka prayas karunga, jis-se ki aap easily turbo-C Compiler par yah pura program type kar Payenge or aapna program time par submit kar Payenge. So friends shuru karte hai.

PROGRAM FOR BISECTION METHOD

# include<stdio.h>
# include<conio.h>
# include<math.h>
# include<string.h>
floateqn(float);
void main()
{
float x1=2,x2=3,x3,z,t, rng=.005;
int i=1;
clrscr();
printf("\n equation is : X^4-34X-9 \n");
do
{
printf("\n iteration %d: \n", i);
x3=(x1+x2)/2;
printf("x3=%f",x3);
z=eqn(x3);
printf("\n f(%f)=%f",x3,z);
if(z>0)
x2=x3;
else
x1=x3;
printf("\n x1=%f\tx2=%f \n",x1,x2);
i++;
}
while((fabs(x1-x2))>0.005);
printf("\n finalanswer=%f \n",x3);
getch();
}

/**** function for given equation***/
floateqn(float x)
{
float f;
f = x*x*x-4*x-9;
return(f);
}

           Output….

Equation is : X^4-34X-9
Iteration 1:
x3=2.500000
f(2.500000)=-3.375000
x1=2.500000     x2=3.000000

iteration 2:
x3=2.750000
f(2.750000)=0.796875
x1=2.500000    x2=2.750000

iteration 3:
x3=2.625000
f(2.625000)=-1.412109
x1=2.625000   x2 =2.750000

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